Switch
statement is used to solve multiple option type problems for menu like program,
where one value is associated with each option. The expression in
switch case evaluates to return an integral value, which is then compared to
the values in different cases, where it matches that block of code is executed,
if there is no match then default block is executed. The general form of switch statement
is:
switch (expression)
{
case value-1:
block-1;
break;
case value-2:
block-2;
break;
case value-3:
block-3;
break;
case value-4:
block-4;
break;
default:
default-block;
break;
}
Points to Remember:
1.
We don't use those expressions to evaluate switch
case, which may return floating point values or strings.
2.
It isn't necessary to use break after each block, but if you
do not use it, all the consecutive block of codes will get executed after the
matching block.
int
i = 1;
switch(i)
{
case 1:
printf("A"); // No break
case
2:
printf("B"); // No break
case 3:
printf("C");
break;
}
Output: A B C
The output was supposed to be only A because only the first case
matches, but as there is no break statement after the block, the next blocks
are executed, until the cursor encounters a break.
3.
default case can be
placed anywhere in the switch case. Even if we don't include the default case
switch statement works.
Example of Switch Statement:
#include<stdio.h>
#include<conio.h>
void main( )
{
int
a,b,c,choice;
clrscr( );
while(choice!=3)
{
printf("\n 1. Press 1 for addition.");
printf("\n 2. Press 2 for subtraction.");
printf("\n 3. Press 3 for exit.");
printf("\n Enter your choice: ");
scanf("%d",&choice);
switch(choice)
{
case 1:
printf("\nEnter 2 numbers: ");
scanf("%d%d",&a,&b);
c=a+b;
printf("%d\n",c);
break;
case 2:
printf("\nEnter 2 numbers: ");
scanf("%d%d",&a,&b);
c=a-b;
printf("%d\n",c);
break;
case 3:
printf("\n Thanks !!! Visit Again !!!");
break;
default:
printf("\n You have passed a wrong key");
printf("\n Press any key to continue");
}
}
getch();
}
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